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08:48:03: Yay :-) (x*y+1)*(x^3199+2)-x^3199-1=0 (mod 8000) -> 2*x*y+1
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15:11:41: Yay :-) (x*y+1)*(x^3199+2)-x^3199-1=0 (mod 8000) -> 2*x*y+1
15:11:51: Modular calculus is really amazing
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20:03:22: * impomatic wonders how to solve for x given y in 2*x*y+1 (mod 8000) = 0
20:05:12: Ah, no solutions :-(